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0=-0.75x^2+3.5x-1
We move all terms to the left:
0-(-0.75x^2+3.5x-1)=0
We add all the numbers together, and all the variables
-(-0.75x^2+3.5x-1)=0
We get rid of parentheses
0.75x^2-3.5x+1=0
a = 0.75; b = -3.5; c = +1;
Δ = b2-4ac
Δ = -3.52-4·0.75·1
Δ = 9.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.5)-\sqrt{9.25}}{2*0.75}=\frac{3.5-\sqrt{9.25}}{1.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.5)+\sqrt{9.25}}{2*0.75}=\frac{3.5+\sqrt{9.25}}{1.5} $
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